Python tkinter文件选择askopenfilename实现方法

引入tkinter库和askopenfilename, askopenfilenames, askdirectory, asksaveasfilename

import tkinter as tk
from tkinter.filedialog import (askopenfilename, askopenfilenames, askdirectory, asksaveasfilename)

其中askopenfilename (这个是”打开”对话框)用来获取文件路径和名称，askopenfilenames获取多个文件， askdirectory获取文件夹路径 （上文有讲到）,asksaveasfilename (这个是另存为对话框)

然后选择文件，并返回路径和文件名

###读取文件并返回文件路径和文件名到文本框
def selectFile():
    path_ = askopenfilename()
    path.set(path_)

输出结果：

代码：

import tkinter as tk
from tkinter.filedialog import (askopenfilename, askopenfilenames, askdirectory, asksaveasfilename)

###读取文件并返回文件路径和文件名到文本框
def selectFile():
    path_ = askopenfilename()
    path.set(path_)


root = tk.Tk()
path = tk.StringVar()

tk.Label(root, text="目标文件:").grid(row=0, column=0)
tk.Entry(root, textvariable=path).grid(row=0, column=1)
tk.Button(root, text="文件选择", command=selectFile).grid(row=0, column=2)

root.mainloop()